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Helga [31]
3 years ago
10

Classify this traingle

Mathematics
2 answers:
Mrac [35]3 years ago
4 0
You have the correct answer on your paper so you should be good if not let me know what else you need:)
lisabon 2012 [21]3 years ago
3 0
You're answer is correct!! You do not need to change anything.
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Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

Hence, log_b(xy)=log_b x+log_b y

3 0
3 years ago
What is the trigonometric ratio for cosC ?
Usimov [2.4K]
Sin C = 24/ 51
hope this helps
5 0
3 years ago
Read 2 more answers
Can someone help please
Alik [6]

Answer:

6

Step-by-step explanation:

base + 2(legs) = 56  (2 legs are the same because it's isosceles)

x + 2(5x - 5) = 56

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11x -10 = 56

11x = 66

x = 6

5 0
3 years ago
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