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ASHA 777 [7]
3 years ago
13

Simplify 13x + 7y - 2x + 6a

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0

Step-by-step explanation:

13x+7y-2x+6a

combine like terms

=13x-2x+7y+6a

=11x+7y+6a

simplified

andreyandreev [35.5K]3 years ago
5 0

For this case we must simplify the following expression:

13x + 7y-2x + 6a

To simplify, we must add similar terms, that is:

13x-2x + 7y + 6a

Remember that different signs are subtracted and the sign of the major is placed. So:

13x-2x + 7y + 6a = 11x + 7y + 6a

Answer:

11x + 7y + 6a

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Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
3 years ago
If 94 people attend a concert and tickets for adults cost $2.5 while tickets for children cost $1.75 and total receipts for the
Tasya [4]

Answer:

52 adults and 42 children attended the concert

Step-by-step explanation:

Given:

Total attendees=94 people

Adults tickets=$2.5

Children tickets=$1.75

Total receipts=$203.5

Let adults=a

Children=c

a+c=94 (1)

2.5a + 1.75c=203.5 (2)

From (1)

a+c=94

a=94-c

Substitute a=94-c into (2)

2.5a + 1.75c=203.5

2.5(94-c) + 1.75c=203.5

235-2.5c+1.75c=203.5

-0.75c=203.5-235

-0.75c=-31.5

Divide both sides by -0.75

-0.75c/-0.75=-31.5/-0.75

c=42

Substitute c=42 into (1)

a+c=94

a+42=94

a=94-42

=52

a=52

Therefore,

52 adults and 42 children attended the concert

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3 years ago
I need help asap with this iready lesson!!!!
Ksju [112]

Answer:

top left

Step-by-step explanation:

8 0
3 years ago
Tom and Jerry enter a race. Tom runs an average of 10 kilometers per hour, and Jerry runs an average of 9 kilometers per hour. I
Zielflug [23.3K]
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3 years ago
Read 2 more answers
10. On one night, a group of 9 rats carried away 45 kg of food. What is the reduced ratio of rats to food weight
GenaCL600 [577]

Answer:

Number of rats : Food weight = 1 : 5

Step-by-step explanation:

Number of rats in the group = 9

Weight of food carried away by them = 45 kg

Ratio of the number of rats and food weight = \frac{\text{Number of rats}}{\text{Weight of food carried by the rats}}

                                                                          = \frac{9}{45}

                                                                          = \frac{1\times 9}{5\times 9}

                                                                          = \frac{1}{5}

Therefore, Number of rats : Food weight = 1 : 5

4 0
3 years ago
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