Find the LCD of the following list of fractions. --14/10, -12/b
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For the 60°'s topmost line, you can find the angle next to it is 120° because it's a straight line. You can do the same for 95° if you put that the angle opposite it is equal already because it's the opposite angle, so you subtract from 180° again to get 85°. When you extend the lines, you can find the alternate interior angles to the 60° and 85°, which are congruent to them. You then get that for both the formed triangles there is one 85° and one 60°, which together with one more angle should equal 180°. Through knowing that the sun of the triangles angles should be 180°, if you subtract the sum of 60° and 85° from 180°, you get the angle of the 3rd angle in the triangles (35°). This angle also forms 180° with x on a line, so 180°-35°=x, which is 145° seemingly.
