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Anastaziya [24]
3 years ago
8

What is 48.4÷ 0.4 cause I don't understand this.

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

The answer is 121

Step-by-step explanation:

So basically it's like dividing 4 from 4 and you get 1

Then 8 from 4 and it would come out as 2

And divide 4 once more from 4 and get 1 again

4÷4=1

8÷4=2

4÷4=1

Then out the answers together and you got 121

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An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
PLEASE Help THIS IS DUE Tomorrow!!!!!!!!!! PLEASE This is urgent
jolli1 [7]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
I'll give you brainiest and lots of points..
irinina [24]
It’s A since 7/8 x (-16) is -14 then -14 x (-7) is 98 and 98 x (-1/14) is -98/14 which gets -7
3 0
3 years ago
What are the solutions to the nonlinear system of equations below? Check all that apply.
Gemiola [76]
The solutions are a and b
5 0
3 years ago
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A horizontal line contains points A, C, B. 2 lines extend from point C. A line extends to point E and another line extends to po
Effectus [21]

Answer:

Option (2).

Step-by-step explanation:

In the figure attached,

A, C and B are the points lying on a straight line.

2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.

Ray CE is the angle bisector of ∠ACD.

That means CE divides ∠ACD in two equal parts.

m∠ACE = m∠DCE

Since m∠ACD = m∠ACE + m∠DCE

                        = 2(m∠ACE)

          m∠ACE = \frac{1}{2}(\angle ACD)

Therefore, option (2) will be the answer.

6 0
3 years ago
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