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Paha777 [63]
3 years ago
13

PLEASE HELP ME!!!! WORTH 10 POINTS!!!

Mathematics
1 answer:
Sidana [21]3 years ago
7 0
<span>slope
m = (1  - 1)/(0 + 2) = 0

(x1, y1) as (-2, 1)

</span><span>point-slope form</span><span>
y - y1 = m(x - x1)
y - 1 = 0(x + 2)
y - 1 = 0
y = 1</span>
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Find the area of a regular hexagon if given a side length of 1.9 to the square root of 3.
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Answer:

28.137 sq. units.

Step-by-step explanation:

Area of a regular hexagon is

A=\dfrac{3\sqrt{3}}{2}a^2

where, a is the side length.

It is given that the side length of the regular hexagon is 1.9\sqrt{3}.

Substitute a=1.9\sqrt{3} in the above formula.

A=\dfrac{3\sqrt{3}}{2}(1.9\sqrt{3})^2

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A=16.245\sqrt{3}

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Therefore, the area of regular hexagon is 28.137 sq. units.

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Sliva [168]

Slope-intercept form:

y = mx + b

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For lines to be parallel, their slopes have to be the SAME.


The given line's slope is 4, so the parallel line's slope is also 4.

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To find "b", plug in the point (-3,5) into the equation.

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Step-by-step explanation:

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