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neonofarm [45]
3 years ago
6

A call center receives 25 callers per minute on average. On average, a caller spends 1 minute on hold and 4 minutes talking to a

service representative. On average, how many callers are "in" the call center
Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

"125 callers" is the right answer.

Step-by-step explanation:

Given values:

Arrival calls rate,

= 25 per minute

Talking time,

= 4 minutes

Hold time,

= 1 minute

The flow time will be:

= 1 \ minute \ + 4 \ minutes

= 5 \ minutes

Flow rate,

= Arrival \ calls \ rate

= 25 \ per \ minute

By using the Little's law,

⇒ WIP = Flow \ rate\times Flow \ time

By substituting the values, we get

            = 25\times 5

            =125

Thus the above is the correct approach.

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Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

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Replacing values, we have

C_{100}^{4}  =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}=  \frac{94,109,400}{24}= 3,921,225

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Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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