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Mariulka [41]
3 years ago
7

A scale model of a school bus is 3 inches long. The actual school bus is 45 feet long. Which statement(s) are true?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

Answer:

The scale of the model is 1 in.:15 ft.

Step-by-step explanation:

In order to find this, first express the terms that you know.

3 in.:45 ft.

Now simplify by dividing both by the greatest common factor, which in this case is 3.

1 in.:15ft.

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What is 2x-3=4(x-5)? And also what is 2x squared=50?
Ierofanga [76]
2x - 3 = 4(x - 5)
2x - 3 = 4x - 20
4x - 2x = 20 - 3
2x = 17
x = 8 1/2

2x² = 50
x² = 25
x = \pm√25
x = \pm5


6 0
3 years ago
One member of the debate team is going to be chosen president. each member is equally likely to be chosen. the probability that
inessss [21]
Let
x-------> <span>the probability that a boy is chosen
B------> </span>number of boys in the debate team
G------> number of girls in the debate team<span>

we know that
B+G=20-----> G=20-B-----> equation 1
</span>probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2

t<span>he probability that a girl is chosen is 2/3 the probability that a boy is chosen
</span>probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4

resolve the equations system
x=B/20
(2/3)*x=[20-B]/20

using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8

number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%

the answer is
number of girls in the debate team is 8

7 0
3 years ago
ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
I need help! if you answer wrong for points I will report you! but hurry this is timed!
anyanavicka [17]

Answer:

it would be 10

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
PLEASE HELP!! A.S.A.P!!!
tresset_1 [31]

tan A = height /base = 2/3

7 0
3 years ago
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