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slavikrds [6]
3 years ago
5

The team manager mixes 0.6 kg of Gatorade powder with water in the 5-gallon water coolers for the football team. Gatorade donate

s new 7-gallon water jugs. How much powder should the manager use in a new 7-gallon cooler to maintain the same Gatorade mixture?
Mathematics
1 answer:
ra1l [238]3 years ago
6 0
Since it's 0.6 kg for 5 gallons, we'd want to find the unit rate aka the amount of kg's per gallon. To find that, we have to see how many times 5 goes into 0.6, which is 0.6/5=0.12 for 1 gallon. Multiply that by 7 to get 0.84 for 7 gallons!
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Which is the value of 2c2d if c = 0.5 and d = 3?<br> A. 0.15<br> B. 1.5<br> C.33<br> D. 6<br> E 15
aksik [14]

Answer:

The answer is D (6).

hope this helps!

4 0
3 years ago
Find the surface area of the three-dimensional figure. ______ cm^2
ki77a [65]
150.88=7.4*3.1+3.1*5+7.4*5+7.4*3.1+7.4*5+5*3.1 thank you
3 0
3 years ago
The box plots show male and females grades in mathematics class: Which of the following best describes the information about the
Arturiano [62]

Answer:

The interquartile ranges are quite close in value.      

Step-by-step explanation:

We have been given two box-plots and we are asked to choose the correct statement about the interquartile ranges.

Since we know that interquartile range is difference between upper and lower quartile.

IQR=Q_3-Q_1

Let us find IQR for the female grades in math.

We can see from box-plot representing female grades that upper quartile is about 90 and lower quartile is about 75.    

\text{IQR of female grades}=90-75

\text{IQR of female grades}=15

Now let us find IQR for the male grades in math.

\text{IQR of male grades}=85-70

\text{IQR of male grades}=15

We can see IQR values for males and females are same, therefore, last statement is true.

4 0
4 years ago
Read 2 more answers
Suppose a ball is thrown upward to a height of h 0 meters. After each​ bounce, the ball rebounds to a fraction r of its previous
gladu [14]

Answer:

A)1st term:45

2nd term:48.75

3rd term:49.6875

4th term:49.921875

B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Step-by-step explanation:

We are given;

h₀ = Initial height of the ball = 30

r = Rebound fraction = 0.25

a) The arithmetic sequence of bouncing balls is given by the following;

Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)

The first term of the sequence is;

S₁ = h₀ + 2h₀r¹

S₁ = 30 + (2 × 30 × 0.25)

S₁ = 45

The second term of the sequence is;

S₂ = h₀ + 2h₀(r¹+r²)

S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75

The third term of the sequence is;

S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875

S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)

S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875

B) The general expression for the nth term of the sequence is;

Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

4 0
3 years ago
Assignment
nignag [31]

Answer: 6 in ^2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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