Question

(05.03 HC) There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B. Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points) Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points) Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically.

Answer 1

Answer:

Step-by-step explanation:

From the information given:

Neighbourhood A = 30  homes and the number increases by 20% each year

Neighbourhood B = 45  homes, and each year 3 new homes are built.

A.

The function representing the numbers of homes in  Neighbourhood A and B are as follows:

For neighbourhood A: f(x) = $\mathbf{30 \times (1.2)^x}$

For neighbourhood B: f(x) =  45 + 3x

B.

After five years;

Neighbourhood A has = $\mathbf{30 \times (1.2)^x}$

Neighbourhood A  = $\mathbf{30 \times (1.2)^5}$

Neighbourhood A  =  74.65 homes

Neighbourhood B: =   45 + 3(5)

Neighbourhood B: =   45 + 15

Neighbourhood B: =   60 homes

C.

To determine how many years the number of homes are the same for neighbourhood A and B, we need to equate both together.

i.e.

$\mathbf{30 \times (1.2)^x= 45 + 3x}$

$\mathbf{ (1.2)^x= \dfrac{45 + 3x}{30}}$

$\mathbf{ (0.4)^x= \dfrac{15 + x}{10}}$

x = 3.3

Thus, after 3.3 years, the number of homes will be the same.