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Hitman42 [59]
3 years ago
7

Maths question!!! The angles in triangle ABC are given in degrees, prove that AB=AC

Mathematics
2 answers:
ra1l [238]3 years ago
8 0
Do 12x+20=40x-8 and solve for x
ra1l [238]3 years ago
5 0
First, find out the value of x to confirm if they are really true. 

We know that all the interior angles of a triangle equal to 180 degrees. 

4x+5x-8+3x+20=180 
12x=180-12 
12x=168
x=168/12 
x=14 

Put in these values of to find if AB=AC. 

(4×14)(3×14+20)=(4×14)(5×14-8) 

Solve for LHS first, 

(4×14)(3×14+20) = 56×62 

=3472 

Solve for RHS next, 

(4×14)(5×14-8) = 56×62

=3472

Since LHS=RHS, AB is also equal to AC. 

Hope I helped :) 
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Answer:

\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

Step-by-step explanation:

Given:

Center of the ellipse is, (h,k)=(-4,-3)

Minor axis length is, 2b=6

A vertex of the ellipse is at (1, -3)

Now, distance between the center and the vertex is half of the length of the major axis.

Using distance formula for (-4, -3) and (1, -3), we get:

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Therefore, the value of half of major axis is, a=5. Also,

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\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

Plug in h=-4,k=-3,a=5,b=3 and determine the equation.

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