3 years ago

Find csc(angle) if tan(angle) = -4/3 and sin(angle) is positive.

1 answer:

Lerok [7]3 years ago

7 0

Answer:

hm?

Step-by-step explanation:

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natali 33 [55]

$\huge \bf༆ Answer ༄$

Let's simply ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: - 5 {x}^{2} (4x - 6 {x}^{2} - 3)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:( - 5x {}^{2} \times 4x) - ( - 5 {x}^{2} \times 6 {x}^{2} ) - ( - 5 {x}^{2} \times 3)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: - 20 {x}^{3} - ( - 30 {x}^{4} ) - ( - 15 {x}^{2} )$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: - 20 {x}^{3} + 30 {x}^{4} + 15 {x}^{2}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:30 {x}^{4} - 20 {x}^{3} + 15 {x}^{2}$

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