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AlekseyPX
4 years ago
7

Help please! i need to find the restrictions to this expression

Mathematics
1 answer:
jarptica [38.1K]4 years ago
5 0

Answer:

x = 7, x = \frac{-1}{5}

Step-by-step explanation:

A restriction can only be found in the denominators and this is when x is a certain number that when plugged in, makes the expression 0 (this makes it undefined, which you cannot have).

<em><u>Since we are only looking at the denominator, you can just ignore the numerator:</u></em>

(x - 7) (5x + 1)

<em><u>To find the restrictions, you must set them equal to 0:</u></em>

x - 7 = 0

5x + 1 = 0

<em><u>Then, solve:</u></em>

x - 7 = 0                                                                                        5x + 1 = 0

  + 7   + 7                                                                                            - 1   - 1

________                                                                                    ________

x = 7                                                                                                 5x = -1

                                                                                                          x = \frac{-1}{5}

If you plug these numbers in, the total outcome would come out to be 0, making the expression undefined, proving that these are the restrictions of the expression.

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When 12x² + kx + 3 and 3x³ + (3k + 2)x² + 28x +17
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Answer:

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Step-by-step explanation:

Hello,

We know that for a real, the polynomial P(x) divided by (x-a) the remainder is P(a)

and as

3x+2=03x=-2x=\dfrac{-2}{3}

so we need

12(\dfrac{-2}{3})^2+k(\dfrac{-2}{3})+3=3(\dfrac{-2}{3})^3+(3k+2)(\dfrac{-2}{3})^2+28\dfrac{-2}{3}+17\\ \ multiply \ by \ 9\\ 12*4-6k+27=-8+4(3k+2)-28*2*3+17*9\\ -6k+48+27=-8+12k+8-168+153\\ -6k+75=12k-15\\ 18k=75+15=90\\ k = \dfrac{90}{18}=\dfrac{15}{3}

hope this helps

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3 years ago
Find f’(x).<br><br> 1. f(x)=x^2-5x+1<br><br> 2. f(x)=10/x
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Answer:

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Step-by-step explanation:

Use power rule and constant rule for the first one:

1) f(x)=x^2-5x^1+1                                (x^n)'=nx^(n-1) and (c)'=0

f'(x)=2x^1-5(1)x^0+0                        

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Use just power rule for last one after a rewrite

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