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AlekseyPX
4 years ago
7

Help please! i need to find the restrictions to this expression

Mathematics
1 answer:
jarptica [38.1K]4 years ago
5 0

Answer:

x = 7, x = \frac{-1}{5}

Step-by-step explanation:

A restriction can only be found in the denominators and this is when x is a certain number that when plugged in, makes the expression 0 (this makes it undefined, which you cannot have).

<em><u>Since we are only looking at the denominator, you can just ignore the numerator:</u></em>

(x - 7) (5x + 1)

<em><u>To find the restrictions, you must set them equal to 0:</u></em>

x - 7 = 0

5x + 1 = 0

<em><u>Then, solve:</u></em>

x - 7 = 0                                                                                        5x + 1 = 0

  + 7   + 7                                                                                            - 1   - 1

________                                                                                    ________

x = 7                                                                                                 5x = -1

                                                                                                          x = \frac{-1}{5}

If you plug these numbers in, the total outcome would come out to be 0, making the expression undefined, proving that these are the restrictions of the expression.

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nlexa [21]

$ PS = \frac{4}{3} x

Solution:

Given PRQ is a triangle.

ST is a line parallel to RQ.

$PT = x, \ PQ = 3x,  \ SR=\frac{8}{3}x

TQ=PQ-PT

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<u>Triangle proportionality theorem,</u>

<em>If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.</em>

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3 years ago
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alukav5142 [94]

The expression of sinU as a fraction is 12/13

Find the diagram attached.

To get the fraction represented by sinU, we will use the SOH CA TOA identity.

From the diagram;

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Since sin theta = opp/hyp

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Learn  more on SOH CAH TOA here: brainly.com/question/20734777

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3 years ago
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3 years ago
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aliina [53]

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D

Step-by-step explanation:

even

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odd

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3 0
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