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2 years ago

What equation represents a line that passes through (4,1/3) and has a slope of 3/4

1 answer:

4 0

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{\frac{1}{3}})
\qquad \qquad \qquad \qquad 
% slope = m
slope = m\implies \cfrac{3}{4}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-\cfrac{1}{3}=\cfrac{3}{4}(x-4)\implies y-\cfrac{1}{3}=\cfrac{3}{4}x-3
\\\\\\
y=\cfrac{3}{4}x-3+\cfrac{1}{3}\implies y=\cfrac{3}{4}x-\cfrac{8}{3}$

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SOLVE EQUATION solve for x | 3x+19 | =13 (absolute value)

egoroff_w [7]

Answer:

x=-2 and -32/3

Step-by-step explanation:

|3x+19|=13

3x+19=13 and 3x+19=-13

x=-2 and x=-32/3

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2 years ago

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What is the slope of the line?

valentinak56 [21]

If you attatch a picture i can help. or message or even write out the points

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2 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

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2 years ago

In a fruit cocktail, for every 15 ml of orange juice you need 25 ml of apple juice and 10 ml of coconut milk. What proportion of

frosja888 [35]

Answer:

3/10 is orange juice.

Step-by-step explanation:

Step 1: Find the total mL in the concoction

15 + 25 + 10 = 50 mL in a fruit cocktail

Step 2: Find the proportion of orange juice in 1 serving (50 mL) of cocktail

15/50 = 3/10

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3 years ago

Which of the following quantities are inversely proportional? WILL GIVE BRAINIEST

Effectus [21]

Answer:

option 1

option 3

option 4

Step-by-step explanation:

Inversely proportional means "one quality increases, the other decreases " or "one quantity decreases ,other increases. " Inverse relantionship, that's it.

option 1:

Since the volume is given as 56 and we know the volume is area of base * height, to keep the volume at constant [56], if height increases, area of base would need to decrease, and vice versa. So Inversely proportional.

option 2:

The time spend in plowing a field with a tractor with increase when we area using more fuel.So more fuel used means more time spent. So these are directly proportional, Not inverse.

option 3:

Since the price is a constant, the amount of length we buy more,the price per one yard HAS to decrease, and vice versa. So ,this is Inverse relantionship.

option 4:

If the number of identical tractors. increase, it will take less time to plow the set 358 acre farm. And vice versa. So this is Inversely proportional as well.

PLEASE MARK ME AS BRAINLIEST!!

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2 years ago

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