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Lunna [17]
3 years ago
12

A woman takes 121212 equal-sized steps. She walks a total of 10 \text { yards}10 yards10, start text, space, y, a, r, d, s, end

text. How many inches long is each step?
Mathematics
1 answer:
kramer3 years ago
5 0

Answer:

30 inches

Step-by-step explanation:

She takes 12 equal sized steps and they all add up to 10 yards.

The length of each step (in yards) is:

10 / 12 = 5/6 yards

The question requires the answer in inches, therefore, we must convert this to inches:

1 yard = 36 inches

5/6 yards = 5/6 * 36 = 30 inches

Each step is 30 inches long.

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3x+6y = 27<br> x + 2y = 11<br> Solve by elimination
AlladinOne [14]

Answer:go0gle

gle come in clutch

Step-by-step explanation:

Next, let's solve 3x+2y = 10 for the variable y. Move the 3x to the right hand side by subtracting 3x from both sides, like this: 3x - 3x = 0. The answer is 2y. The answer is 10-3x.

4 0
2 years ago
Is the line of best fit y=-2.9114x+40.7464 or y=-2.9114x+46.5693 ? Please help i’m in a rush!
Colt1911 [192]

Answer:

line of best fit: y = -2.9114x + 46.569

Step-by-step explanation:

Plugging in your table into Excel, it turns out that y = -2.9114x + 46.569  provides a better fit of the data points into the line.  Please see the attached image for details.

Hope this helps.

3 0
2 years ago
The apother is 4 m and a side is 5.8 m. What is the area
jekas [21]

Answer:

58 m^2.

Step-by-step explanation:

The  area of one of the 5 triangles is:

1/2 * 5.8 * 4 = 11.6 m^2

So the area of the pentagon

= 5 + 11.6

= 58 m^2

4 0
2 years ago
Read 2 more answers
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
2 years ago
Does the following represent the Transitive Property? If p = q and q = r then q = t.
BabaBlast [244]
No its not.
because there is no relation between p,q and t.
here, p=q andq=r. so p=r is transitive.
but p not equal to t.

hope it helps u..
6 0
3 years ago
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