Problem 1
<h3>Answers:</h3>
- Terms = -4a, -7b, 5, c
- Variables = a, b, c
- Coefficients = -4, -7, 1
- Constants = 5
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Explanation:
Each term is separated by a plus sign. If we had something like -4a-7b, then rewrite it as -4a+(-7b). This works because subtraction is really adding a negative. Example: 2-3 = 2+(-3)
So the original expression becomes -4a+(-7b)+5+c and we see there are four terms here.
The terms with the variables are -4a, -7b and c. The variables are simply letters so we just say a,b,c are the variables. The coefficients are the numbers to the left of the variables. For the term c, it is really 1c, so the coefficient is 1.
The constant is the term without a variable multiplied with it. So that would be the 5. As the name suggest, the constant term does not change based on whatever the variables are.
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Problem 2
<h3>Answers:</h3>
- terms = 7, -5h, -2, -k
- variables = h,k
- coefficients = -5, -1
- constants = 7, -2
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Explanation:
We'll follow the same idea as problem 1.
Rewrite 7-5h-2-k as 7+(-5h)+(-2)+(-k) and we see there are four terms.
The term -k is the same as -1k, so the coefficient is -1
The variables this time are h,k as those are the two letters that show up.
The constants are 7 and -2 because no variables are attached to them.
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I'll let you do the rest. If you're still stuck, then please let me know
