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3 years ago

A) Round 98984 to 1 significant figure.

1 answer:

4 0

To find the significant figure you must start from the left.
If you see a 0 then you mustn’t count it and look at the next number.
In this case we have a 9 as the first digit on the left.
We are rounding to 1 significant figure so our answer would be 100000.
Hope this helped!

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard

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Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81$

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{30732 - 30393}{472.81}$

$Z = 0.72$

$Z = 0.72$ has a pvalue of 0.7642.

X = 30054

$Z = \frac{X - \mu}{s}$

$Z = \frac{30054 - 30393}{472.81}$

$Z = -0.72$

$Z = -0.72$ has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

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4 years ago

If graphed in the plane, would the line y=5x-2 pass through the point (4,15)

yulyashka [42]

Answer:

Step-by-step explanation:

Using substitution, subs in the points given

(15) = 5(4) - 2

15 = 20 - 2

Because the 2 sides are NOT equal the line would not pass through the point

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4 years ago

Abdul flips a weighted coin 64 times and gets 16 tails. Based on experimental probability, how many of the next 40 flips should

sergij07 [2.7K]

Answer:

yes, Abdul should expect to come up tails.

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3 years ago

Convert 31 minutes to seconds

In-s [12.5K]

Answer:

Step-by-step explanation: 1,860 Seconds Is Equal To 31 Minutes Hope It Helped

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4 years ago

A large truck has two fuel tanks, each with a capacity of 150 gallons. Tank 1 is half full, and Tank 2 is empty.

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Answer:

1) $G(t) = 75 + \frac{23}{4}t\\$

2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

Step-by-step explanation:

1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:

$\frac{150}{2} = 75 gallons$

Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:

$5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}$

Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:

$G(t) = 75 + \frac{23}{4}t\\$

2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have

$G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons$

After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

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3 years ago