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3 years ago

WELPPP !!!!!!!!!!!!!!!!

Mathematics

1 answer:

Vsevolod [243]3 years ago

3 0

The answer is A. To do this you must add 9 to both sides and you get (x+3)^2=27 and you must solve from there

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You need to buy tissue paper sheets to cushion gifts being placed inside a box. The box is 12 inches wide by 16 inches long. The

Kay [80]

Answer:

Area of tissue paper is 384 square inches.

Step-by-step explanation:

Given:

Length of box = 16 inches.

Width of the box = 12 inches.

We need to find find the area of the tissue paper.

But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.

Hence Framing in equation form we get;

Area of tissue paper = $2(length\ of \ box \times width \ of \ box)$

Hence Substituting the given values we get;

Area of tissue paper = $2(12\times 16) = 2\times 192 = 384 in^2$

Hence Area of tissue paper is 384 square inches.

7 0

2 years ago

Can someone help me... What is the answer

serious [3.7K]

z = 2y

Step-by-step explanation:

$x = 2y$ ..... (given)

$z = x$ ... (exterior alternate angles)

$z = 2y$

8 0

2 years ago

If (1)=3 and f(n)=f(n-1)-1 then find the value of f(6)

katrin [286]

Answer:

f(1) = 3

f(n) = f(n-1) - 1

Otherwise,

f(n) = f(1) - (n-1)

=> f(6) = 3 - 5 = -2

Hope this helps!

8 0

2 years ago

Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean

Maurinko [17]

Answer:

$N= 4543$ Labrador retrievers

Step-by-step explanation:

We know that the mean $\mu$ is:

$\mu = 62.5$

and the standard deviation $\sigma$ is:

$\sigma=2.5$

The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:

$P(X$

We calculate the Z-score for X =65

$Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1$

$P(X$

Looking in the table for the standard normal distribution we have to:

$P(Z$ .

Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:

$N = P(X$

$N = 0.8413*5400$

$N= 4543$ Labrador retrievers

6 0

2 years ago

A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s

ANTONII [103]

<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula. We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

We are given the function:

$h=-5t^{2}-3t+38$

Where,

$a=-5\\b=-3\\c=38$

Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$

Since negative time does not exists, the ball will hit the ground after:

$t=2.473s=2.47s$

Have a nice day!

4 0

2 years ago

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