Perform the indicated multiplication:
<span>7p-(3p+4)= -2(2p-1) + 10
becomes
7p - 3p - 4 = -4p + 2 + 10
Group like terms:
7p - 3p + 4p = 2 + 10 + 4
8p = 16 => p = 2 (answer)</span>
Answer:
Step-by-step explanation:
![[-5+(-7)]^2-(7+3)^2](https://tex.z-dn.net/?f=%5B-5%2B%28-7%29%5D%5E2-%287%2B3%29%5E2)
Resolving Parenthesis
=> 44
1. Let x = #
2. "Five less than six times a number" can be written as: 6x - 5
3. "is at least" is the same as "greater than or equal to" and can be written as: >=
4. "nine subtracted from two times that number" can be written as: 2x - 9
5. the equation is: 6x - 5 >= 2x - 9
6. solve for x by grouping the x variable terms on one side and the constants on the other side:
6x - 5 >= 2x - 9
-2x +5 -2X +5
4x >= -4
7. divide each side by 4, and you get: x = -1
