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2 years ago

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Twice a number added to a smaller number is 5. The difference of 5 times the smaller number and the larger number is 3. Let x re

present the smaller number and y represent the larger number. Which equations represent the situation? UV-5

1 answer:

Sergio [31]2 years ago

6 0

Answer:

1) 2Y+X=5

2) 5X-Y=3

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A petting zoo owner is building an enclosure for his farm animals. He needs 353 feet of fencing. The supply store sells fencing

jolli1 [7]

353/12 =29.41. But will have to round up to 30 so the answer is 30

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2 years ago

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Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-3,1) and (2,-1) is $y=-\frac{2}{5}x-\frac{1}{5}$

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2 years ago

Name three radii of Circle S.

Talja [164]

Answer:

circle S radii SU, ST, SR

Circle U radii UT, US, UR

Step-by-step explanation:

Radii start in the middle of the circle to the end of the circle.

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3 years ago

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to draw a ray, plot an endpoint and select an arrow. select an endpoint to change it from closed to open. select the middle of t

Ronch [10]

Answer:

it's C

Step-by-step explanation:

I think I don't know I just guessed

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2 years ago

Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.

Dafna1 [17]

Answer:

$\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

Step-by-step explanation:

When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

$\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

The figure EFG and its reflection E'F'G' are shown in the diagram below.

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2 years ago