Twice a number added to a smaller number is 5. The difference of 5 times the smaller number and the larger number is 3. Let x re
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Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is =
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is =
Thus change in moment is:
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:
Hence, the constant force exerted on the ball by the wall is 119.68 N.