Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
The plane has intercepts at (1, 0, 0), (0, 2, 0), and (0, 0, 6), so we can parameterize the surface
by
where
and
. Now
so the surface integral reduces to
We need to compute 5% out of $60K.
Tax: 5%×60000=5/100×60000=5×600=$3000
Answer: $3000
