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mars1129 [50]
3 years ago
9

Which number is irrational? A. 3 over 8 B. square root of 56 over 8 end root C. fraction numerator square root of 36 over denomi

nator square root of 4 end fraction D. Syntax error from line 1 column 53 to line 1 column 60. Unexpected '0'.
Mathematics
1 answer:
Rasek [7]3 years ago
7 0
The correct answer is letter <span> D. Syntax error from line 1 column 53 to line 1 column 60. Unexpected '0'. In order for a number to be considered as irrational when there is no possible ratio for that number. Among the four choices, choice D only tells us that the possible ratio or fraction has a denominator of Zero.</span>
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3 years ago
The triangle below is equilateral. Find the length of side x to the nearest tenth.
Gemiola [76]

Answer:

\sqrt{\frac{15}{2} } or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}

x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

x^{2} =10-\frac{10}{4}

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x=\sqrt{\frac{15}{2} }

This approximately equals 2.738

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