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Vladimir79 [104]
3 years ago
10

Please answer quickly

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

Step-by-step explanation:

4^3 * 4^4 = 4^(3+4) = 4^7

4^7/4^9 = 4^(7-9)

= 4^-2 = 1/4^2

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Jocelyn wants to purchase a
scoundrel [369]

Answer:

Step-by-step explanation:

Total cost b = 23.95 + 7.65c

7 0
3 years ago
Write the ratio as a fraction in simplest form. 10 ft to 5 yds
Vlada [557]
10/5÷5/5=2/1 or 2 so all you had to do was put the numbers over each other and simplify
6 0
3 years ago
Of 350 solitaire games that jay played, he won 154 times. what percent of the games did jay win?​
ludmilkaskok [199]

Answer:

44.044%

Step-by-step explanation:

To find the answer we first have to find the value of each percent, to do this we divide 100 by 350, that gets us approximately 0.286. We know that he won 154 of them we then multiply 154 by 0.286 to get the percentage of games he won and we get 44.044.

5 0
3 years ago
Read 2 more answers
The measure of an angle is three more than twice its supplement. What is the measure of the angle?
Zinaida [17]

Answer: the angle is 1°+n×120°

1°, 121°, 241°


Step-by-step explanation:

Angles are taken modulo 360°, so 363° = 3°.

Angle plus supplement gives 180°.

Let a be angle, s be supplement of a.

So s = 180-a. Given a = 3 + 2s

a = 3 + 2(180 - a)

a = 3 + 360 - 2a = 363 - 2a


3a = 363° or 3° or 723°

a = 121° or 1° or 241°


a = 1°

s = 179°

2s = 358°

2s+3 = 361° = 1° (modulo 360)


a = 121°

s = 180-121 = 59°

2s = 118°

2s + 3 = 121°, as required.


a = 241°

s = 360+180-241 = 540-241 = 299

2s = 598

2s + 3 = 601 = 241 (modulo 360)


7 0
3 years ago
a tour-bus operator sold $1,517 worth of tickets for a trip to Niagara Falls. Each tickets cost the same amount and could be pai
prisoha [69]

We will make use of the concept of prime factors for solving this question. The prime factors of 1517 are:

1517=37\times 41

So, as can be clearly seen the Niagara Fall tour operator can either sell 37 tickets for $41 each or 41 tickets for $37 each.

Now, we know that we cannot reach $37 using just three bills. Thus, the only option left to us is $41 which can be broken down into three bills of $20,$20 and $1. This satisfies our condition.

Thus the cost of a ticket was $41 and 37 such tickets were sold.

3 0
3 years ago
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