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Snowcat [4.5K]
3 years ago
6

Graph the equation y=2x. Fill in the missing values in the table.

Mathematics
2 answers:
Taya2010 [7]3 years ago
8 0

Answer:

in this order (0,0) (1,2) (2,4) (3,6)

Step-by-step explanation:

pls mark brainliest

marishachu [46]3 years ago
8 0

I can't see pictures, but to graph y=2x, you have to make 2x into slope form.

Just write 2 as a fraction, or 2/1. 2 is the rise, and 1 is the run. So start at the origin, or (0,0), and go up 2 units, then 1 unit right. So you start at (0,0), then now you should be at (1,2). Repeat the process to make a straight line.

---

hope it helps

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Read 2 more answers
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
4 years ago
Slope between (0,0) and (1,1)
CaHeK987 [17]
The slope would be 1/1x, or just 1x or 1.
8 0
3 years ago
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