Answer:
Margin of error = 4.21 ounces
Step-by-step explanation:
According to the Question,
- Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces
Therefore, Sample mean = 31 ounces , Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces
- Thus, Margin of error =
× σ / √n ( at α=.010 is 1.645)
Putting The Values, We get
1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21
Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces
<span>Simplifying
w + -11 = 1.3
Reorder the terms:
-11 + w = 1.3
Solving
-11 + w = 1.3
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 11 + w = 1.3 + 11
Combine like terms: -11 + 11 = 0
0 + w = 1.3 + 11
w = 1.3 + 11
Combine like terms: 1.3 + 11 = 12.3
w = 12.3
Simplifying
w = 12.3 <--- (Answer)
Happy studying ^-^</span>
You have to plug in the given numbers and perform each operation. Let me know if you have questions. The answers are circled.
Answer:
K(x, y) —> K’(-x, y - 7)
Step-by-step explanation:
