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icang [17]
2 years ago
14

PLEASE HELP ME! How do you factor out the coefficient of a variable?? Example: 5c - 15

Mathematics
2 answers:
SpyIntel [72]2 years ago
7 0
Divide both by a number that can go into both terms so it will be 5 . 
\frac{5c-15}{5} which is 5(c-3)
allochka39001 [22]2 years ago
3 0
5c-15=\\
5(c-3)
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Solve this equation -3x+1+10x=x+4
Salsk061 [2.6K]

Answer: x=\frac{1}{2}

Explanation:

We have been given with the equation -3x+1+10x=x+4

We will collect the terms that are written in variable of x in one side and the constant values on the other side we will get

-3x+10x-x=4-1

After simplification we will get  6x=3

which implies x=1/2

When x from right hand side shift  will shift to left hand side it will change its sign and similarly when 1 from left hand side shift to right hand side change its sign.

Therefore, x=1/2

3 0
3 years ago
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AleksandrR [38]

Answer:

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3 years ago
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arsen [322]
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7 0
2 years ago
I need help please with this 1 problem
Lyrx [107]

Answer:

See below, please

Step-by-step explanation:

We know

f(x) =  {x}^{2}  + 3x - 7

g(x) = 3x + 5

h(x) = 2 {x}^{2}  - 4

Hence

f(g(x))

=  {(3x + 5)}^{2}  + 3 \times (3x + 5) - 7

= (9 {x}^{2}  + 30x + 25) + (9x + 15) - 7

= 9 {x}^{2}  + 39x + 33

h(g(x))

= 2 \times  {(3x + 5)}^{2}  - 4

2 \times (9 {x}^{2}  + 30x + 25) - 4

= 18 {x}^{2}  + 60x + 50 - 4

= 18 {x}^{2}  + 60x + 46

(h - f)(x)

= h(x) - f(x)

= (2 {x}^{2}  - 4) - ( {x}^{2}  + 3x - 7)

=  {x}^{2}  - 3x + 3

(f + g)(x)

= f(x) + g(x)

= ( {x}^{2}  + 3x - 7) + (3x + 5)

=  {x}^{2}  + 6x - 2

5 0
2 years ago
ASAP PLEASE!! The morning temperature on Saturday was 21.5°. By 10:00 it had warmed up 6.25°. What is the new temperature?
zaharov [31]

The temperature would be (21.5 + 6.25) which is 27.75


4 0
3 years ago
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