Answer:
The female will not inherit a sex linked disorder if her father suffers rather "have chances or the disorder if the mother is the carrier" for the disorder.
Explanation:
A female has 2 X chromosome, which she got from her parents each. The females will get the disorder or the defective gene if the mother has defective X chromosome or if the father is carrying the same disorder from his father(grandfather). In both the cases the female will be the carrier and have chances to inherit the defect to the offspring. But the female will not affect as the male will. As the female has 2 X chromosomes, and hence the dominant X will compensate for the error in recessive X.
In prophase 1:
Chromosomes become visible, crossing-over occurs, the nucleolus disappears, the meiotic spindle forms, and the nuclear envelope disappears.
In metaphase 1:
The pairs of chromosomes (bivalents) become arranged on the metaphase plate and are attached to the now fully formed meiotic spindle. The centrioles are at opposite poles of the cell.
The reactions of glycolysis are made up of ten steps, out of the ten step three are irreversible, this is because, these reactions have large negative free energies The three steps that are irreversible are:
1. Phosphorylation of glucose.
2. Phosphorylation of glucose 6 phosphate and
3. Transfer of phosphate from phosphoenolpyruvate to ADP.
The answer is a the first one.
Flowering plants produce male and female cells. The male cells are called pollen and the female cells are called ova. When a flowering plant is fertilized, it produces offspring in the form of seeds. However, not all plants reproduce flowers. Simpler plants, like mosses, lack these specialized structures.
