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Simora [160]
3 years ago
13

4 1 __ / ( - __ ) 5 15

Mathematics
1 answer:
Allushta [10]3 years ago
5 0
4 over 5 divided by (-1 over 15)

that means:

\frac{4/5}{-1/15} = -\frac{4*15}{1*5} =- \frac{4*3*5}{5}=-4*3=-12


I hope you got satisfied



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Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
2 years ago
Please solve the problem and show all steps, thank you.a-c=d+r, for a
Delicious77 [7]

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Step-by-step explanation:

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6 0
2 years ago
How do i solve my math problem (5 carry 3 on top) carry 3 on top again
kvasek [131]
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REY [17]

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divide <em>35</em> and <em>42</em> by the GCF<em> (7)</em>, and you should get 5:6 as your answer.

3 0
3 years ago
What is the value of x? Enter your answer in the box.
Illusion [34]

Answer:

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Step-by-step explanation:

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Hope this helps!

7 0
2 years ago
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