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3 years ago

Give an example of both rational and an irrational number that falls between 24 and 25

Mathematics

1 answer:

levacccp [35]3 years ago

6 0

Both 24 and 25 are rational. They can be turned into a fraction by putting a 1 as the denominator.

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What is Y=2(3x+6)(5x-4)

Sliva [168]

Answer:

y=30x^2+36x+48 OR f(x)=30x^2+36x+48

This is an exponential function/exponential graph. Hope I helped!

Step-by-step explanation:

Given: y=2(3x+6)(5x-4)

Use the distributive property!: y=(6x+12)(5x-4)

Use the distributive property!: y=(5x(6x+12)-4(6x+12))

Use the distributive property!: y=(30x^2+60x)-(24x+48)

Remove parenthesis: y=30x^2+60x-24x+48y=30x^2+36x+48 OR f(x)=30x^2+36x+48

This is an exponential function/exponential graph. Hope I helped!

8 0

3 years ago

Please help mee pleaseee

nalin [4]

Answer:

The exact answer in terms of radicals is $x = 5*\sqrt[3]{25}$

The approximate answer is $x \approx 14.62009$ (accurate to 5 decimal places)

===============================================

Work Shown:

Let $y = \sqrt[5]{x^3}$

So the equation reduces to -7 = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since $y = \sqrt[5]{x^3}$ and y = 5, this means we can equate the two expressions and solve for x

$y = 5$

$\sqrt[5]{x^3} = 5$

$x^3 = 5^5$ Raise both sides to the 5th power

$x^3 = 3125$

$x = \sqrt[3]{3125}$ Apply cube root to both sides

$x = \sqrt[3]{125*25}$

$x = \sqrt[3]{125}*\sqrt[3]{25}$

$x = \sqrt[3]{5^3}*\sqrt[3]{25}$

$x = 5*\sqrt[3]{25}$

$x \approx 14.62009$

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3 years ago

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Minchanka [31]

Answer:

120.

Step-by-step explanation:

She adds $5 to her account each week. If 0 weeks have gone by, then her account hasn't changed.

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3 years ago

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Hi need help on a test for math

enyata [817]

Answer:

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Step-by-step explanation:

i did use a calculator tho

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Tape diagram to subtract 33-19

Tpy6a [65]

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