Question

Find the slope of a line perpendicular to 2x-y=16

Answer 1

Answer: $\dfrac{-1}{2}$

Step-by-step explanation:

The standard equation of a line in intercept form is given by :-

$y=mx+b$, where m is the slope of the line.               (1)

Given equation of a line : $2x-y=16$

It can be written as :

$y=2x-16$

By comparing to the equation (1) , we have

$m=2$

Also, the product of slopes of two perpendicular lines is -1.

Let p be the slope of the line perpendicular to $2x-y=16$, then we have

$p\times 2=-1\\\\\Rightarrow\ p=\dfrac{-1}{2}$

Hence, the slope of the line perpendicular to $2x-y=16$ = $\dfrac{-1}{2}$

Answer 2

The slope would be -1/2