1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brums [2.3K]
3 years ago
14

Help me please pretty plese

Mathematics
2 answers:
ankoles [38]3 years ago
5 0
9,7,8 respectively for part 2
noname [10]3 years ago
4 0
The answer would be 9
You might be interested in
If sin theta = cos theta then find the value of theta
Ksenya-84 [330]

Step-by-step explanation:

\because \sin  \theta =  \cos  \theta  \\   \\ \therefore \: \sin  \theta =  \sin(90 \degree -   \theta)  \\   \\ \therefore \:  \theta =  90 \degree -   \theta \\   \\ \therefore \:   \theta + \theta=  90 \degree \\  \\ \therefore \:  2\theta =  90 \degree \\  \\\therefore \:  \theta =   \frac{90 \degree }{2} \\  \\ \huge \orange{\boxed{\therefore \:   \theta =   45 \degree}}\\  \\

4 0
3 years ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
3 years ago
What is one of the solutions to the following equations? y2+x2=53<br> Y-x=5
Olenka [21]
(1)  y² + x² = 53
(2)  y - x = 5 ⇒ y = x + 5

subtitute (2) to (1)

(x + 5)² + x² = 53      |use (a + b)² = a² + 2ab + b²

x² + 2x·5 + 5² + x² = 53

2x² + 10x + 25 = 53     |subtract 53 from both sides

2x² + 10x - 28 =0     |divide both sides by 2

x² + 5x - 14 = 0

x² - 2x+ 7x - 14 = 0

x(x - 2) + 7(x - 2) = 0

(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7

subtitute the values of y to (2)

for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3

Answer: x = 2 and y = 7 or x = -7 and y = 3
4 0
3 years ago
The ratio of water and milk in a mixture is 2:3, what percent of water is mixed in the mixture?
elena-s [515]
40% water 60% milk

reason:
if you make then go to 100 by multiplying 2:3 by 2 you get 4:6 and then add a 0 at the end and there’s your answer
5 0
2 years ago
Read 2 more answers
A tire has a diameter of 184 cm what is the circumference of the tire
viktelen [127]
Here is your answer

diameter of tyre= 184cm

So,

Circumference=\:{pi}×d

= 3.14 × 184 cm

= 577.76 cm

HOPE IT IS USEFUL
8 0
3 years ago
Other questions:
  • Consider that lines a and b are parallel. What is the measurement of ∠12?
    13·1 answer
  • 4(x+3)= -24<br><br> solve for x
    5·1 answer
  • Simplify -3+6i-(-5-3i)-8i​
    14·1 answer
  • 2x= 20<br> Choose<br> 2 3 4 5
    6·1 answer
  • WILL GIVE BRAINLIEST IF FAST AND RIGHT
    5·1 answer
  • I’ll give u brainiest pls help me im so lost
    6·1 answer
  • Simplified<br> 3.2-5.1n-2n+8=
    12·2 answers
  • The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the
    15·1 answer
  • 1. Simplify .........​
    5·1 answer
  • Which one is steeper?<br> y=3x+7 <br> y=1/2x+9
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!