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3 years ago

The temperature was 10 degrees below 0 and dropped 24 degrees. What is the new temperature?

Mathematics

2 answers:

Lilit [14]3 years ago

5 0

34 degrees 0 i beleive

Gemiola [76]3 years ago

4 0

(-10) - 24 = (-34) degrees

Hope this helped!

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3 years ago

You deposit $6000 in an account earning 2% interest compounded monthly. How much will you have in your account in 15 years?

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3 years ago

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1 year ago

Identify the vertex, the axis of symmetry, the maximum or minimum value, and the range of the parabola for y=x^2+6x+13

charle [14.2K]

Answer:

Step-by-step explanation:

First we can determine the x value of our vertex via the equation:

$x=\frac{-b}{2a}$

Note that in general a quadratic equation is such that:

$ax^2+bx+c$

In this case a,b and c are the coefficients and so a=1, b=6 and c=13.

Therefore we can determine the x component of the vertex by plugging in the values known and so:

$x=\frac{-b}{2a}=\frac{-6}{2(1)}=\frac{-6}{2}=-3$

Now we can determine the y-component of our vertex by plugging in the x-component to the equation and so:

$f(x)=x^2+6x+13\\\\f(-3)=(-3)^2+6(-3)+13\\\\f(-3)=4$

Therefore our vertex is (-3,4). Now in vertex our x component determines is the axis of symmetry so the equation for axis of symmetry is:

x=-3

Similarly, the y-component of our vertex is the minimum or maximum. In this case it is the minimum you can determine this because a is positive meaning that the parabola will point up, and so the equation for the minimum is:

y=4

The range of the formula is the smallest y-value meaning the minimum y=4 and all real numbers that are more than 4, mathematically:

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3 years ago

Solve x/5 - 1=7? help please !!

xxTIMURxx [149]

First, add 1 on both sides of the equation to begin to isolate x

x/5 = 8

Now, to isolate x, multiply both sides of the equation by 5/1

$\frac{x}{5}$ · $\frac{5}{1}$ = $\frac{5x}{5}$ = x

x= 7 · 5/1 = 7 · 5 = 35

x = 35

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2 years ago