4 years ago

RS=5y+5, ST=3y+7, and RT=12y-20 what is the value of y?

1 answer:

7 0

Since S is a point on the line RT, therefore:
RS+ST = RT
5y+5+3y+7 = 12y-20
separate the variables and solve to get thevalue of y as follows:
5+7+20 = 12y-3y-5y
32=4y
y = 8

substitute in the equation of each line to get its length as follows:
RS = 5y+5 = 5(8)+5 = 45
ST = 3y+7 = 3(8)+7 = 31
RT = 12y-20 = 12(8)-20 = 76

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german

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3 years ago

Help Please?! ?????????????

andrezito [222]

Answer:

Ed's answer of $\frac{3}{8}$ is correct because he divided $\frac{1}{4}$ by $\frac{2}{3}$ to get his answer.

Step-by-step explanation:

To solve for m in $\frac{2}{3}m=\frac{1}{4}$ you want to isolate m by dividing by $\frac{2}{3}$ on both sides, therefore he divided $\frac{1}{4}$ by $\frac{2}{3}$ to get his answer of $\frac{3}{8}$ , and his answer is correct.