The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
<h3>What is the area of a heptagon?</h3>
Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.
The area of the regular heptagon is found out using the following formula.

Here, (<em>a</em>) is the length of the heptagon.
A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
Learn more about the area of a heptagon here;
brainly.com/question/26271153
Answer:
the answer is 10
Step-by-step explanation:
(8+4+14+16+8)/5
See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Answer:
1. X3, 15x - 10y = 80 15x - 7y = 51
-17y = 29
2. 8 = 1/60 + a. 8 - 1/60 = 7.98333333333
6 = 1/80 + b. 6 - 1/80 = 5.9875
13.9708333333
3. I genuinely dont know sorry.
4. Pencil = $0.05. Pen = $1.05
Step-by-step explanation: