Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
31.13
Step-by-step explanation:
If you look carefully, you will find a semicircle and a triangle.
The total area is =
- r = 4 - 0 = 4
- base = |-4-0 | = 4
- height = 14 - 9 = 5
So if we put the values:
As Louis is only leaving a 20% tip on the pretax bill, this means he's leaving 20% of $27.62
The best thing to do is to find 10% and double it.
27.62/10= 2.76 (as it rounds down)
2.76*2= 5.52
Therefore, you've got to add $5.52 to $27.62
$5.52+$27.62= $33.14
Hope this helps :)
The coefficient would be c I believe I may be wrong
