The interquartile range is 5!
Lol
Answer:
p = - 5, p = - 1
Step-by-step explanation:
Given
-
= 
Multiply through by the LCM of (p - 5)(p + 3)
3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis
3p² + 9p - 2p + 10 = p² - 5p
3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )
2p² + 12p + 10 = 0 ← divide through by 2
p² + 6p + 5 = 0 ← in standard form
(p + 1)(p + 5) = 0 ← in factored form
Equate each factor to zero and solve for p
p + 1 = 0 ⇒ p = - 1
p + 5 = 0 ⇒ p = - 5
Answer:
y =7
x =14
Step-by-step explanation:
Since this is a right triangle we can use trig functions
tan 30 = opp /adj
tan 30 = y/ 7 sqrt(3)
7 sqrt(3) tan 30 = y
7 sqrt(3) * 1/ sqrt(3) =t
7 =y
sin 30 = opp/ hyp
sin 30 = 7/x
x sin 30 =7
x = 7/ sin 30
x = 7 / 1/2
x = 14
-4/6 times 2 is -8/12
x - 8/12= x + 2/12
0=10/12
0=5/6
but since 0 does not equal 5/6, this will be no solution