Let ΔABC be an obtuse triangle with sides a, b, c, that lie
opposite the angles A, B, C; with radius r of inscribed circle and
radius R of circumscribed circle; p semiperimeter. For obtuse triangle you can use all known area formulas:
1.
; (the area is equal to half of product of two sides and sine of angle that lies between these sides);
2.
;
3.
(Heron's formula);
4.
;
5.
.
Let
x = pounds of peanuts
y = pounds of cashews
z = pounds of Brazil nuts.
The total pounds is 50, therefore
x + y + z = 50 (1)
The total cost is $6.60 per pound for 50 pounds of mixture.
The total is equal to the sum of the costs of the different nuts.
Because the cost for peanuts, cashews, and Brazil nuts are $3, $10, and $9 respectively, therefore
3x + 10y + 9z = 50*6.8
3x + 10y + 9z = 340 (2)
There are 10 fewer pounds of cashews than peanuts, therefore
x = y + 10 (3)
Substitute (3) into (1) and (2).
y + 10 + y + z = 50
2y + z = 40 (4)
3(y + 10) + 10y + 9z = 340
13y + 9z = 310 (5)
From (4),
z = 40 - 2y (6)
Substitute (6) into (5).
13y + 9(40 - 2y) = 310
-5y = -50
y = 10
z = 40 - 2y = 40 - 20 = 20
x = y + 10 = 20
Answer:
Peanuts: 20 pounds
Cashews: 10 pounds
Brazil nuts: 20 pounds
What do you need?
2log 3/8
= -0.85
Answer:
dont get cote with the link below
Step-by-step explanation:
https://www.symbolab.com/solver/step-by-step/2x%5E%7B2%7D-7%3D-7
Just did this one.
Answer: 7/3 or about 2.3, choice (d).
Step-by-step explanation:
R-P= (3,-7). the displacement vector.
P+x(R-P) moves to x times distance between
P+(R-P) = R moves to 100% of the distance.
Q = P+2/3(R-P)
= (-2,7)+2/3(3,-7)
= (-2,7)+(2,-14/3)
= (0,7-14/3)
= (0,7/3)
= (0,2.3333...)
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