The amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
<h3>How to Solve Algebra Word Problems?</h3>
The concentrations of apple and grape juice in the two different juice types are given as;
Juice A:
(2/3) apple
(1/3) grape
Juice B:
(1/3) apple
(2/3) grape
Let a be how much juice A is in the mixture;
Let b be how much juice B is in the mix.
Thus;
²/₃a + ¹/₃b = 10 ------(eq 1)
¹/₃a + ²/₃b = 8 ------(eq 2)
Solving both equations simultaneously gives us;
a = 12 and b = 6
Thus, the amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
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The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.
I need this answer to please when you get the answer will you let me know thank you!!
Answer: -$6,500
Step-by-step explanation:
Here we could , use the arithmetic progression where
T(2020 - 2010) = a + ( n - 1 )d
T10 = a + ( 10 - 1 )d --------------- 1
a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.
Note since it decreases the common difference d = -$3,500.
Now substitute for the values in the equation above.
T10 = 25,000 + 9 x -3,500
= $25,000 - $31,500
= -$6,500 (deficit )
