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Leona [35]
4 years ago
7

How would I solve (-2-2i)(-4-3i)(7+8)

Mathematics
1 answer:
siniylev [52]4 years ago
5 0
(-2-2i)(-4-3i)(7+8)=\\
15(-2-2i)(-4-3i)=\\
15(8+6i+8i-6)=\\
15(2+14i)=\\
30+210i
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Answer:

P(X=0) = 0.7158

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Step-by-step explanation:

Number of defective laptops = 3

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If the school chooses 2 laptops from this lot, the number of defectives (X) could be 0, 1, or 2.

For zero defectives:

P(X=0) = \frac{17}{20} *\frac{16}{19}\\P(X=0) = 0.7158

For one defective:

P(X=1) = \frac{17}{20} *\frac{3}{19}+\frac{3}{20} *\frac{17}{19}\\P(X=1) = 0.2684

For two defectives:

P(X=2) = \frac{3}{20} *\frac{2}{19}\\P(X=2) = 0.0158

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4 years ago
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