Answer:
P(X=0) = 0.7158
P(X=1) = 0.2684
P(X=2) =0.0158
Step-by-step explanation:
Number of defective laptops = 3
Number of normal laptops = 17
If the school chooses 2 laptops from this lot, the number of defectives (X) could be 0, 1, or 2.
For zero defectives:

For one defective:

For two defectives:

I came up with 4+x/2 Idk if you have to go smaller
Answer:
Step-by-step explanation: 4a³ + 24ab² - 25b³
(In other words B)
Answer:
1 1/8
Step-by-step explanation: