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3 years ago

K(a)= 4a-4, Find k(-9)

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

We simply replace a with -9

k(-9) = 4 * -9 - 4

k(-9) = -40

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What is the distance between the points (-2, 4) and (10, -1)?

Anarel [89]

Answer:

Step-by-step explanation:

D=(-2-10)2 + (4-(-1))2

=(-12)2 + (5)2

=144 + 25

=169 then put under radical

then the answer is 13

4 0

3 years ago

If the lengths of two sides of a triangle are 6 and 7, the length of the third side may be

Ghella [55]

Answer:

The third side may be between 1 and 13 units

Step-by-step explanation:

Let the missing side is x.

According to the triangle inequality theorem, the sum of any two sides of a triangle is greater than the third side.

<u>We have inequalities:</u>

6 + 7 > x ⇒ x < 13
6 + x > 7 ⇒ x > 1
7 + x > 6 ⇒ x > - 1

<u>The common solution is:</u>

1 < x < 13

5 0

2 years ago

Find 356*27+537*373-235*73=

sesenic [268]

Answer:

Using PEMDAS the answer would be 192758

Step-by-step explanation:

(356*27)+(537*373)-(235*73)=

9612+200301-17155=

Solve

192758

Happy learning!

--Applepi101

5 0

3 years ago

1). Which events are independent?

Brilliant_brown [7]

Number 1 is probably D

5 0

2 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago