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Nina [5.8K]
3 years ago
11

How many solutions does this system have?

Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0

Answer:

1

Step-by-step explanation:

There can be 0, 1 or infinitely many solutions. 0 if they are parallel and are different lines, 1 if the slopes are different, and infinitely many if they are the same line.

2x - 4y = 8

x + y = 7

Change to y = mx + b

y = (1/2)x - 2

y = -x + 7

The slopes are different so there is 1 solution.

Hope this helps Please mark as brainliest and have a blessed day

Ilya [14]3 years ago
6 0

Answer:

it has 1 solution

Step-by-step explanation:

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Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

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If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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