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Shalnov [3]
3 years ago
8

Point G’ has coordinates (- 5, 2) If it was reflected across the y-axis, what were the coordinates of its pre image?

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

B. (5,2)

Step-by-step explanation:

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A pitcher of iced tea holds 128 ounces. A large orange cooler holds 1792 ounces of iced tea. How many pitchers of iced tea will
Marysya12 [62]

Answer:

C

Step-by-step explanation:

Ounces held by cooler devide by ounces held by a pitcher since we want to find how many pitchers goes to the cooler

8 0
2 years ago
If a point is originally located at (2,9) and is translated 4 units to the right and 7 units up, what would its new
aliina [53]

Given:

The point is (2,9).

It is translated 4 units to the right and 7 units up.

To find:

The coordinates of new point.

Solution:

The point is translated 4 units to the right and 7 units up. So, the rule of translation is

(x,y)\to (x+4,y+7)

The point is (2,9). Using the above rule, we get

(2,9)\to (2+4,9+7)

(2,9)\to (6,16)

Therefore, the coordinates of new points are (6,16).

5 0
3 years ago
A quadrilateral with two sets of parallel sides and four right angles is a
Musya8 [376]
Its a parallelogram
thats the answer
5 0
3 years ago
Read 2 more answers
Find the length , in centimeters , if the width is 48 <br><br> 1. 10 centimeters
ruslelena [56]
It is 40 becuase points and due
6 0
3 years ago
(04.04 MC)
sp2606 [1]

Answer:

y = x^2/ 60 + 15

=>( x - h)^2 = 4a[ (x^2/6 + 15) - k ].

Step-by-step explanation:

Okay, in order to solve this question very well, one thing we must keep at the back of our mind is that the representation for the equation of a parabola is given as ; y = ax^2 + bx + c.

That is to say; y = ax^2 + bx + c is the equation for a parabola. So, we should be expecting our answer to be in this form.

So, from the question above we are given that "the satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground"

We will make an assumption that the point on the ground is (0,0) and the focus is (0,30). Thus, the vertex (h,k) = (0,15).

The equation that best describes the equation of the satellite is given as;

(x - h)^2 = 4a( y - k). ------------------------(1).

[Note that if (h,k) = (0,15), then, a = 15].

Hence, (x - 0)^2 = (4 × 15) (y - 15).

x^2 = 60(y - 15).

x^2 = 60y - 900.

60y = x^2 + 900.

y = x^2/ 60 + 15.

Hence, we will have;

(x - h)^2 = 4a[ (x^2/6 + 15) - k ].

5 0
3 years ago
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