All categories

3 years ago

Find the GCF of 27x^2 and 45x^3y^2

Mathematics

1 answer:

Inga [223]3 years ago

6 0

Step-by-step explanation:

27x² = 3*3*3*x*x

45x³y² = 3*3*5*x*x*x*y*y

Now

GCF = 3 * 3 *x * x = 9x²

You might be interested in

If the side length is increased by a factor of 3, how much larger is the perimeter of a face of the new cube?

mr_godi [17]

Answer:

A) 72cm

Step-by-step explanation:

Hope this helped

4 0

2 years ago

Read 2 more answers

The reciprocal of 18 is. The reciprocal of is 2/3 is

Leno4ka [110]

Answer:

1/18

3/2

Step-by-step explanation:

18 = 18/1 if the reciprocal means to flip the denominator and the numerator then just witched them so it would be 1/18

2/3 would be 3/2

4 0

2 years ago

Which our equivalent to -11/4

katrin [286]

-11 divided by 4 and -11/4

5 0

2 years ago

Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of

GaryK [48]

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is $KE=\frac{1}{2}mv^2$

Where

KE is the kinetic energy

m is the mass

v is the velocity

Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

KE of 1st mass is:

$\frac{1}{2}mv^2$

KE of 2nd mass is:

$\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4$

Hence, the kinetic energy of the 2nd mass is 4 times the first.

6 0

3 years ago