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xenn [34]
2 years ago
9

I need help pleasee!!!!

Mathematics
1 answer:
andre [41]2 years ago
8 0

Answer:

Your answer is c

Step-by-step explanation:

the two inequalities are x =< 1 and x =>2 which is shown by the number line in option c

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Help!!!!!!!! 2 questions!
Bad White [126]
The one on the left is b and the one on the right is -1.
5 0
3 years ago
Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya
Gnoma [55]

Answer:  If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

y=5x-1\\\\y-5x=-1

For the case of Howard :

Equation will be

y=5x+1\\\\y-5x=1

For the case of Vincent :

y=4x+5\\\\y-4x=5

Since First two equations are parallel so it has no solution.

Reason:

y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}

Hence, if two pair is parallel then it has no solution.


8 0
3 years ago
Read 2 more answers
Please help me find the area of this shape
oee [108]

Answer:

Step-by-step explanation:

15 x 7 = 105

The gap is either 9 x 7 =63 or 12 x 7 = 84

105 - 84 = 21

105 - 63 = 42

So the shaded area is either is 21 or 42

7 0
2 years ago
PLEASE HELP FAST pleaaaaaaaaaaaaaaaaaaaaaaase
Eduardwww [97]

Answer:

i think the answer is C. 1.5w^2 + 7.5w + 9

6 0
2 years ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
2 years ago
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