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3 years ago

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to print tickets, a printer charges $45 setup fee plus $2.00 per ticket. Write an algebraic expression for the cost of t tickets

. What is the total cost of 350 tickets?

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

equation is 45+2.00t. the price of 350 tickets would be 700... but the total cost is 745

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maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

<u>1. Subsittute n = 6 into the equation:</u>

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

<u />

<u>2. Substitute n = 5 into the equation:</u>

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u> $a_1$ <u />

$a_4=3a_{3}-5a_{2}-4a_{1}$

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Answer:

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∠s = ∠LGM

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Set them equal to each other to get:

$\frac{y}{h}$ = $\frac{h}{x}$

Solve:

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