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Naily [24]
4 years ago
8

A drug store stocked 672 bottles of some kind of medicine.

Mathematics
1 answer:
Tpy6a [65]4 years ago
4 0

Answer:

48

Step-by-step explanation:

672÷2=336

336÷7=48

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The volume of a room is 400 cu. m and its height is 25 m. Find the cost of carpeting the floor of the room at 5 paisa per sq. cm
madam [21]

Answer:

Step-by-step explanation:

This only works if the room is a prism shaped, or cylinder.  

Volume of a prism or cylinder is area of he base times height.  So since we know the height and volume we can fand the area.

V = h*B

B = V/h

B = 400/25

B = 8

This is a very narrow room, anyway, the area of the base, which we want to carpet is 8 square meters. Can you figure out how much it will cost since each square meter will cost 5?

5 0
4 years ago
Find the equation of the line with x-intercept -3 and y-intercept 4. (In slope-intercept form)
dmitriy555 [2]
Y=mx+b

(-3,0)
(0,4)

Change of y / change of x
4/3

Y=4/3x-3
7 0
3 years ago
V/7=5<br> Solve for v<br> (I need help right now)
adoni [48]

Answer:

V=35

Step-by-step explanation:

\frac{V}{7} =5

Start by multiplying by 7 on both sides:

V=35

3 0
3 years ago
Read 2 more answers
Can anyone help me with this?? i dont know how to get letter h.
MAVERICK [17]
This can be solved by using the 30 60 90 triangle. The 30-60 side is equal to 2x, here it is 2x=18. The 60-90 side is equal to x. So this side is 18/2=9. The 30-90 side is by the way equal to the root of x, so here the root of 18
4 0
2 years ago
From a shipment of 65 transistors, 6 of which are defective, a sample of 5 transistors is selected at random.
Vladimir79 [104]

Answer:

a) 8259888

b) 34220

c) 45057474

Step-by-step explanation:

Given,

The total number of transistor = 65,

In which, the defective transistor = 6,

So, the number of non defective transistor = 65 - 6 = 59,

Since, out of these transistor 5 are selected,

a) Thus, the number of ways = the total possible combination of 5 transistors = {65}C_ 5

=\frac{65!}{(65-5)!5!}

=8259888

b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors = {6}C_3\times {59}C_2

=\frac{6!}{(6-3)!3!}\times \frac{59!}{(59-2)!\times 2!}

=20\times 1711

=34220

c) The number of sample without any defective transistor = The possible combination of 0 defective transistor = ^6C_0\times ^{59}C_5

=1\times 45057474

=45057474

5 0
3 years ago
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