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GREYUIT [131]
3 years ago
15

Simplify (7a+10b)-(4a-6b). a. 3a2+16b b. 3a+4b c. 3a+16b d. 11a+4b

Mathematics
1 answer:
Daniel [21]3 years ago
4 0
(7a + 10b) - (4a - 6b)
(7a - 4a) + (10b - (-6b))
3a + (10b + 6b)
3a + 16b
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Can someone help me with this
nordsb [41]

Answer:

63.2

Step-by-step explanation:

So, we can break this shape into 2 shapes. A trapezoid and a rectangle.

For the trapezoid, we can do the formula.

                                                 ((2.8 + 7.2)4)/2 = 20

Next, we can do the rectangle.

                                                 6 x 7.2 = 43.2

Now we can add them up and get our final answer.

                                                 43.2 + 20 = 63.2

5 0
3 years ago
The table below shows the number of kool-aid packets needed to make different amounts of fruit punch. What is the total number o
madreJ [45]

Answer: 30

Step-by-step explanation:

4 0
3 years ago
Use the equation to complete an algebraic proof that proves the answer is x = 7/6. Write your proof in your journal and upload y
Komok [63]

Answer:

x=7/6

Step-by-step explanation:

subtract the 4x from both sides of the equation

(2x+6)-4x=4x-3-4x

find common denominator

(2x+6)/5+(5(-4)x)/5=4x-3-4x

then combine fractions

(2x+6+5(-4)x)/5=4x-3-4x

then multiply the 5&4

(2x+6-20x)/5= 4x3-4x

combine terms

(-18x+6)/5= -3

then multiply everything by 5

-18x+6= -15

subtract the 6 from both sides

-18x= -21

divide -21 by -18

(-21)/(-18)=x

find greatest common multiple (3) and solve

x = 7/6

5 0
3 years ago
What is the geometric sequence?​
melisa1 [442]

Answer:

a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-one number called the common ratio. hope this helped :)

Step-by-step explanation:

6 0
4 years ago
Helllllppp!!!!!!!!!!!!11 marking brainliest!
aalyn [17]

Hello!

Let the unknown number be x.

Subtract 5:

x-5

Double the result: (multiply the result times 2):

2(x-5)

Hope everything is clear.

Let me know if you have any questions!

#KeepLearning

:-)

4 0
2 years ago
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