Solve this math problem

How do you solve this problem? I’m really stressed and don’t know how, can someone take me step by step through it? It’s really

Marina CMI [18]

The answer to 4\|256 is 4, since we can find the square root of 256, which is 16, we can find the square root of the square root, which is 4, so, 4^4 is 256 is your answer

4 0

3 years ago

Read 2 more answers

Enrollment at Roosevelt Middle School is being reviewed by the school staff. The table gives the numbers of boys and girls in gr

tekilochka [14]

Grades 6 and 8 have proportional ratio

8 0

3 years ago

The width of a rectangle is 4x−9.5 feet and the length is 9.5x+10 feet. Find the perimeter of the rectangle.

ipn [44]

Answer:

.037 feet

Step-by-step explanation:

perimeter = the sum of all four sides so

perimeter = (4x-9.5) + (9.5x + 10) + (4x - 9.5) + (9.5x + 10) = 27x = 1

therefore x = 1/27 = .037 feet

7 0

3 years ago

Read 2 more answers

You go to Sandy's and want to order a pizza. You can choose from thin or thick crust; white sauce or red sauce; and pepperoni, s

RSB [31]

Answer:

2 crusts

2 sauces

4 toppings

2x2x4= 16 combinations

4 0

3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

4 years ago