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emmasim [6.3K]
2 years ago
13

Billy starts counting backwards by 7, starting at 5907. when he reaches a single-digit number, he stops counting. what is the nu

mber he stops at ?
pls give me a correct method to do it. thx

best answer brainliest
Mathematics
1 answer:
Akimi4 [234]2 years ago
5 0
If you do 5907/7 you will get 843.85714
Do 843*7=5901.
Then do 5907-5901=6
The final answer you will get is 6.
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What's 67% as a decimal?
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0.67, because when you have a percent like that you just need to move the decimal 2 places to the left.
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3 years ago
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A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (
NikAS [45]

Answer:

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.

another way is

This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.

So,

(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA

Step-by-step explanation:

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6 0
2 years ago
What is the y-intercept of this equation?<br> y= 2/9x +13
Ksju [112]

Answer:

13

Step-by-step explanation:

y=mx+b

b= y-intercept

5 0
2 years ago
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A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
KN bisects ZJKM. If mZNKJ = 7x-9 and<br> m2JKM = x + 3, find m2JKN.
BaLLatris [955]

Answer:

Step-by-step explanation:

7x - 9 = x + 3

6x - 9 = 3

6x = 12

x = 2

7(2) - 9 + 2 + 3

14 - 9 + 5

5 + 5 = 10

5 0
3 years ago
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