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3 years ago

Add the following- 3/5,- 7/10and 4/15

Mathematics

1 answer:

maxonik [38]3 years ago

4 0

Answer:

-31/30

Step-by-step explanation:

-3/5 - 7/10 + 4/15 = -31/30

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the probability of rolling a number less than 3 on a number cube is 2/6. Jennifer rolls 60 times. how many times should Jennifer

saveliy_v [14]

Answer:23

Step-by-step explanation:

7 0

3 years ago

A gas pump fills 2^-2 gallon of gasoline per second. how many gallons does the pump fill in one minute?

astraxan [27]

Answer:

The gas pump filling the gallons in 1 minute will be: 15

Step-by-step explanation:

Given that a gas pump fills 2^-2 gallon of gasoline per second.

As there are 60 seconds in 1 minute.

Thus,

Gas pump filling the gallons in 1 minute will be:

$60\:\times 2^{-2}$

$=60\times \frac{1}{2^2}$ ∵ $a^{-b}=\frac{1}{a^b}$

$\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}$

$=\frac{1\times \:60}{2^2}$

$=\frac{60}{2^2}$

$=\frac{2^2\times \:3\times \:5}{2^2}$

$=3\times \:5$

$=15$ gallons in one minute

Therefore, the gas pump filling the gallons in 1 minute will be: 15

6 0

3 years ago

Can I get help on this question or an example? I would really appreciate it.

gulaghasi [49]

Answer:

B = 0.95m + 29.95

Step-by-step explanation:

this is really y = mx + b

m is a rate, 0.95 per mile

b is the y-intercept, or the price you pay no matter what, 29.95

8 0

3 years ago

The result of =ROUND(513.2413,2) is __

timama [110]

Answer:

513.24132

Step-by-step explanation:

None of the numbers are large enough to make the next number higher. Therefore that would just be your answer.

5 0

2 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

4 years ago

Add the following- 3/5,- 7/10and 4/15​

Add the following- 3/5,- 7/10and 4/15