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Rzqust [24]
3 years ago
5

Every 6th customer at the flower shop receives a free rose, and every 9th customer receives a free lily.

Mathematics
2 answers:
ollegr [7]3 years ago
8 0

Answer: 18th customer

Step-by-step explanation: Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48

Multiples of 9: 9, 18, 27, 36, 45, 54, 63, 72

tatiyna3 years ago
4 0

Answer:18th costumer

Step-by-step explanation:

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The durations of a random sample of 16 commercials are below (in seconds). find the mean, median, and mode of these durations. 3
UkoKoshka [18]
First arrange in ascending order of time:-

7, 8, 10, 12, 14, 15, 18, 20, 26, 30, 30, 30, 35, 35, 42, 55

MOde is the value occuring mos  = 30.

Median is the mean of 2 middle numbers = (20 + 26) / 2 = 23

Mean = sum of the 16 numbers  / 16  =  387/16  = 24.2
7 0
4 years ago
Is this comparison true 2.29 < 2.129
AURORKA [14]

No.

The value of 2.29 is greater than, not less than, the value 2.129.

2 and 1 are in the same location in each number: the tenths position. 2 is larger than 1 is, and thus 2.29 is larger.

4 0
3 years ago
Read 2 more answers
Help me plz in few minutes test <br>show all work and explain plz
Rus_ich [418]
The median is the vertical line in the box

and the interquartile range is the length of the box itself

So the answer would be B as its median is greater than 80 and it has the large <span>interquartile range...


</span>

I hope that helps!



4 0
3 years ago
Make b the subject<br>a=4b+2/3-b​
Rasek [7]

Answer:

b = \frac{3a-2}{9}

Step-by-step explanation:

Given

a = 4b + \frac{2}{3} - b, that is

a = 3b + \frac{2}{3}

Multiply through by 3 to clear the fraction

3a = 9b + 2 ( subtract 2 from both sides )

3a - 2 = 9b ( divide both sides by 9 )

\frac{3a-2}{9} = b

6 0
3 years ago
Doah builds a gardening shed for her father's birthday. Based on the measurements below, what is the volume of the shed Doah bui
san4es73 [151]

Answer:

cant see whats below so i cant exactly help wothout it

Step-by-step explanation:

i said it was so and so it was

4 0
3 years ago
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