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harkovskaia [24]
3 years ago
7

What Is The Length Of Side BD?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0
This is a rectangle, meaning that all angles are right angles and all sides opposite to one another have equal length.

Since the length of CD is 24, the length of AB must also be 24.
Angle B is a right angle because this is a rectangle.

See anything? I'll you a hint. We have a right triangle with only one missing value.

What do we use to solve for missing lengths in a right triangle? The Pythagorean theorem, of course!

a^2+b^2=c^2

The length of c (the hypotenuse) is 26.
The length of a (one leg) is 24.
The length of b is unknown and we want to find it.

24^2+b^2=26^2

576+b^2=676

Subtract 576 by both sides.

b^2=100

Take square root of both sides.

b=10

The length of the missing leg is 10, meaning that the length of BD is 10.

This is what you should be needing. Enjoy!
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Answer:

15/2

Step-by-step explanation:

5 3/4 - 1/6x = 4 1/2

move the variable to it's own side.

5 3/4 - 4 1/2 = 1/6x

change the subtracting side to have common denominators

5 3/4 - 4 2/4 = 1/6x

1 1/4 = 1/6 x

divide both sides by 1/6, same thing as multiplying both sides by 6 (reciprocal)

30/4 = x

reduce: 15/2 = x

8 0
3 years ago
Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is 13.4 years with a s
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Answer : 0.0129

Step-by-step explanation:

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Sample size : n=40

Let X be the random variable that represents the age of fleets.

We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.

For z-score,

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x=14

z=\dfrac{14-13.4}{\dfrac{1.7}{\sqrt{40}}}\approx2.23

By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-

P(x\geq 14)=P(z\geq2.23)\\\\=1-P(z

Hence, the required probability = 0.0129

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3 years ago
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GREYUIT [131]

Answer:

jk

Step-by-step explanation:

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His change was $2.28. 
</span>
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