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Ray Of Light [21]

3 years ago

7

20pts how do you solve 3x-2y=14?

1 answer:

Furkat [3]3 years ago

4 0

X(3) - Y(2) = 14. So you need numbers that will multiply by 3 and a number that multiply by 2 that will equal 14.
The x can be 10 (equals 30) and then y can be 8 (equals 16).
30 subtracted by 16 equals 14.

ANSWER:

X = 10 Y = 16
3(10) - 2(8) = 14

Hope this helped. Have a great day. A thank you and (or) brainliest is always appreciated. Goodbye!

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Hey! pls help i’ll give brainliest

grandymaker [24]

Answer:

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2 years ago

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The area of the parallelogram shown is (35x2 + 46x +15) square meters. If its base is (5x + 3) meters, find

attashe74 [19]

Answer:

(7x + 5)m

Step-by-step explanation:

area = base * height = (35x2 + 46x +15) m²

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7 0

2 years ago

Find the value of a and of b for which<br>(a) the solution of x2 + ax < b is<br>-2<x < 4

KengaRu [80]

Answer: $a = -2$

$b = 8$

Step-by-step explanation:

Given :

$x^{2} +ax$

re - writing the equation , we have

$x^{2} +ax-b$

we need to find the value of a and b for which -2<x < 4 , this means that the roots of the quadratic equation are -2<x < 4.

The formula for finding the quadratic equation when the roots are known is :

$x^{2}$ - sum of roots(x) + product of root = 0

sum of roots = -2 + 4 = 2

product of roots = -2 x 4 = -8

substituting into the formula , we have:

$x^{2} -2x-8=0$ , which could be written in inequality form as

$x^{2} -2x-8$

comparing with $x^{2} +ax-b$ , it means that :

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3 0

2 years ago

7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)

serg [7]

Answer:

$-\frac{x^2y^2}{2}$

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

$\frac{x^2y^4z^3 }{2y^2z^3}$

Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

5 0

2 years ago

Which of the following is true about the expression square root of 3*2

baherus [9]

Answer:

B

Step-by-step explanation:

$\sqrt{3}*2=3.464101615137755‬$ so it is equal to an irrational number.

2 is rational, and $\sqrt{3}$ is irrational, because it is equal to $1.732050807568877‬$

Hope this helps you. Please mark brainliest! Have a nice day!

7 0

3 years ago