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2 years ago

Find the value of y when x=11 8x+6y=28

Mathematics

1 answer:

kondor19780726 [428]2 years ago

7 0

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I need explanation and answer please,thanks.

Alla [95]

What’s the question?

3 0

2 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

2 years ago

Please help asap 10 points

shepuryov [24]

Answer: 4

Step-by-step explanation: 18/6 =3 so do 12/3 and it will give you 4

5 0

3 years ago

Read 2 more answers

1. 5(2x + 1) = 35<br> I need help what’s the answer showed work

Airida [17]

Answer:

x=3

Step-by-step explanation:

5(2x+1)=35

Step 1: Simplify both sides of the equation.

5(2x+1)=35

(5)(2x)+(5)(1)=35(Distribute)

10x+5=35

Step 2: Subtract 5 from both sides.

10x+5−5=35−5

10x=30

Step 3: Divide both sides by 10.

x=3

5 0

2 years ago

Algebra 2 question need help.

MrMuchimi

Answer: Choice C

h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

===========================================

Explanation:

When reflecting the function f(x) over the y axis, we replace every x with -x and simplify like so

f(x) = -x^4 - 2x^3 + 3x^2 - 4x + 5

f(-x) = -(-x)^4 - 2(-x)^3 + 3(-x)^2 - 4(-x) + 5

f(-x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

Note the sign changes that occur for the terms that have odd exponents (the terms -2x^3 and -4x become +2x^3 and +4x); while the even exponent terms keep the same sign.

The reason why we replace every x with -x is because of the examples mentioned below

-----------

Examples:

The point (1,2) moves to (-1,2) after a y axis reflection

Similarly, (-5,7) moves to (5,7) after a y axis reflection.

As you can see, the y coordinate stays the same but the x coordinate flips in sign from negative to positive or vice versa. This is the direct reason for the replacement of every x with -x.

4 0

2 years ago